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So, if you were coming from another programming language, and you looked at something like this, you might assume that it's going to do-- that's 10 divided by 5,
minus 1. But in APL, of course, it's 10, divided by 5 minus 1.
And it doesn't give you the result you were thinking of.
minus 1, 2 minus 2-- very simple.
1 minus 1 divided by 3 dot plus 1 divided by 5 minus ba, ba, ba, ba.
by minus 1.
So this becomes minus 1/2 mv squared minus v,
It's S1 minus 1, because we're missing the 1.
We integrate x minus 1/2.
A square root of minus 1.
It has the property minus 1, 1/2, 1, and so on.
Knowing that probably n minus 1 of them will be really bad, but you'll discover which is the one that's really good.
disposable income to a minus 1% and we become very gifted uh Ardent
through n minus 1 is n divisible by X and then at the end if you got uh all
that square root of minus 1 to it you have what's called the complex numbers and they're an incredible system if you like you put one little thing in you put
previous hidden state 18 minus 1 as input will also include the question at
There's a coefficient to x squared minus 1, et cetera.
Things like the square root of minus 1.
So the electron is charge minus 1, sort of by definition.
2 to the power of n minus 1.
So it's the elasticity minus elasticity minus 1, where this E or epsilon might be something like 2,
electron lies between 10 to the minus 1 planck mass and 10 to the minus 30 plagma okay whatever our electron it's a big range it's a huge range
So say alpha x is 1 and beta equals minus 1.
So all these coefficients have to be either 1 or minus 1, but if you fill that in, then the only two possible answers
And the slope of this is close to minus 1/4, minus because it's negative.
They're of the form 2 to the power of p minus 1, where p is also a prime number.
I can just write that as NFA at T minus 1, so that the change in the net foreign asset position comes from one of two sources.
all what you seen before which is your YT minus 1 YT minus 2 etc and also all
I mean, I'll put a minus 1 in for it or something like that-- any kind of substitution.
And we get x, the minus 1/2 is this constant of integration that's picked out.
They come from the infinite expansion of the function x over e to the x minus 1.
In binary, 2 to the n minus 1 is 111111111.
from negative in the first portfolio to positive in the last portfolio from minus 1.5 to 7.70 so again this could just be
And for more than 30 years, plus or minus 1 or 2%, that was the situation.
if you take any a any number a in the range 0 through n minus 1.
then you think of how you can solve equations then what about x squared equals minus 1 well there's no real number which has to satisfies that so
But if we fill it in here, we get 1 times minus 1, which is just minus 1, plus minus 1 times 1, which is, again, minus 1,
Say alpha x is 1, and now it's alpha z that is minus 1.
Well, in that case, we get 1 times minus 1.
So, again, we get minus 1, plus minus, 1 times 1, again, minus 1.
If I were to read the equation out loud, it would say R mu nu minus 1/2Rg mu nu equals 8 pi GT mu nu.
But multiply them by this very complicated 4n, 4n minus 1 divided by 2n.
And the amount of rice, it becomes 2 the 64 minus 1,
As a result, if I look here at this a T minus 1 minus LT minus 1.
Well, then, we get 1 squared, which is 1, equals minus 1 squared, which is also 1, so that satisfies the top equation.
And in fact, if you look at this top equation, the only numbers that satisfy this relation is 1 and minus 1.
And the result that the some of the integers, we can debate about whether it's equal to minus 1/12 or whether it should be assigned a value minus 1/12.
And so what that means is-- and that's why we get the right answer if you like, which is minus 1/12.
And when you cut this thing off and try to regulate it in a smoother way, then the minus 1/12 emerges much more naturally.
And yet when you start writing down the physics of electrons, for example, it's got the square root of minus 1 sitting in there.
So you have imaginary number-- so somebody decided, well, what if I take the square root of minus 1?
Yeah, the Golden Ratio, the Golden Ratio conjugate, what Golden Ratio minus 1.
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